Question

Most Jet fuel has an average molecular formula of C13H28 and a density of 804 g/L. Calculate the moles of carbon that are released from the fuel when a jet travels from Charlotte, NC to Los Angeles, CA, a distance of 3900 km. Assume the jet consumes 13L of fuel per Km

Answer 1

Jet consumption of fuel = 13 L/km , Total distance travel= 3900 km

Total fuel consumption= $13\times 3900=50700$ L,

Density of fuel = 804 g/L

Mass of fuel = $Volume\times density= 50700\times 804=40762800 g$

Molecular mass of fuel= $C_{13}H_{28}= 12\times 13 + 28\times 1=184 g/mole$

Total mole of $C_{13}H_{28}=\frac{40762800}{184}=221536.956$ mole

Mole of C=$13\times 221536.95=2879980.434$ mole of C