Question

The addition of 9.54 kJ of heat is required to raise the temperature of 225.0 g of a liquid hydrocarbon from 20.5oC to 45.0oC. What is the heat capacity of this hydrocarbon?

Answer 1

$q = mcΔt \\ 9540 = 225.0 \times s \times (45.0 -20.5) \\ c = \frac{9540}{5512.5} \\ c = 1.73 \;J/gC$