Calculate the solubility of Au(OH)3 in water (Ksp=5.5×10−46)(pH=7)
pH+pOH=14pH + pOH = 14pH+pOH=14
POH=14−pHPOH=14-pHPOH=14−pH
pOH=14−7pOH=14-7pOH=14−7
pOH=7pOH=7pOH=7
[OH−]=10−pH[OH^{-}] =10^{-pH}[OH−]=10−pH
[OH−]=10−7[OH^{-}] =10^{-7}[OH−]=10−7
=[OH−]=1×10−7M=[OH ^{-}] =1×10^{-7}M=[OH−]=1×10−7M
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