How many moles of liquid ammonia NH3 are formed when 175.6 kJ are removed during condensation? (23.3 KJ/Mol)
Moles of NH3NH_{3}NH3 ;(175.6kJ×123.3)(\frac{175.6kJ×1}{23.3})(23.3175.6kJ×1)
=7.536moles.
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