Answer to Question #170835 in General Chemistry for taiya

Question

  A solution is made by adding 25mL of toluene to a beaker of benzene. If the mixture is 33% toluene, what was the volume of the benzene in the mixture?

Answer 1

Benzene percentage =100-33=67%

If 33%=25mL

Then 67%=?

$=\frac {67×25}{33}=50.76mL Benzene.$