How much of 0.1 F HC2H3O2 is required to make 600 ml of solution with a pH of 5.0?
PH = -log (M)
Hence M = anti log (-pH)
M = anti log (-5.0)
M"= 1.0\u00d710^{-5}"
Moles "=(1.0\u00d710^{-5})\u00d70.6=6.0\u00d710^{-6} moles"
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