Question

What weight of lactic acid must be dissolved in a liter solution to produce a hydronium concentration of 1 x 10^-3 F?

Answer 1

concentration or molarity = 1 ×10^-3 M

Volume = 1L

Molarity = $\frac{no. Of moles of solute}{volume of solution}$

1×10^-3 = $\frac{moles}{1}$

moles of lactic acid = 1×10^-3 mol

weight of lactic acid = 1×10^-3 ×90.08

= 90.08×10^-3 = 0.09008 g