Answer to Question #170527 in General Chemistry for Tori B Mooney

Question

how many liters of Br₂ will be produced from 3.71g of KBr in the following reaction?

2KBr+ F₂ to 2KF+ Br₂

Answer 1

n(KBr) = 3.71 / 119 = 0.0312 mol

n(Br₂) = 0.0312 / 2 = 0.0156 mol

m(Br₂) = 160$\times$0.0156 = 2.496 g

V(Br₂) = 2.496 / 3.1 = 0.805 ml

Answer: V(Br₂) = 0.805 ml.