H3PO4 (aq) ⇌ H + (aq) + H2PO4 - (aq) Ka = 7.2 x 10 -3
Give the equilibrium constant expression for the reverse reaction.
The backward equilibrium costant
Kequilibrium=Con.H3Po4/con.H+. con.H3Po4-
. =Ka/con.H+. con.H3Po4-
. =7.2*10-3 /con.H+. con.H3Po4-
Comments
Leave a comment