Question

Write the Kc expression for the reversible reaction of CH₃COOH done at equilibrium conditions

Answer 1

Reversible reaction :-

CH₃COOC₂H₅ (aq) + H₂O (l) $\leftrightarrow$ CH₃COOH (aq) + C₂H₅OH (aq)

K_c = $\frac{[CH_3COOH][C_2H_5OH]}{[CH_3COOC_2H_5]}$