What is the ΔH° for the following reaction (in kJ/mol)?
2 Na (s) + 2 H2O (l) → 2 NaOH (aq) + H2 (g)
From the given info, we know the amount of heat released when 2 moles of Na is reacted. We're asked for the heat per 0.5 moles. So, (368.6 kJ/2mol)0.5000 mol = 92.15 kJ released. Therefore, ΔH = - 92.15 kJ
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