Question

What is the ΔH° for the following reaction (in kJ/mol)?

2 Na _(s) + 2 H₂O _(l) →  2 NaOH _(aq) + H_2 (g)

Answer 1

From the given info, we know the amount of heat released when 2 moles of Na is reacted. We're asked for the heat per 0.5 moles. So, (368.6 kJ/2mol)0.5000 mol = 92.15 kJ released. Therefore, ΔH = - 92.15 kJ