N2(g) + 3H2(g)=2NH3(g)
what is the number of molecules of ammonia, NH3 produced if 6.072dm3 of nitrogen gas in STP is reacted completely with hydrogen gas
V (N2) = 6.072 dm3;
n (N2) = V/Vm; n = 6.072 dm3/22.4 dm3 = 0.27 mole;
if n (N2) = 0.27 mole then n (NH3) = 0.27 * 2 = 1.35 mole;
N (NH3) = NA * n = 6.02*1023 * 1.35 mole = 8.127*1023
Answer: N (NH3) = 8.127*1023
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