Question

N₂(g) + 3H₂(g)=2NH_3(g)

what is the number of molecules of ammonia, NH3 produced if 6.072dm3 of nitrogen gas in STP is reacted completely with hydrogen gas

Answer 1

V (N₂) = 6.072 dm3;

n (N₂) = V/V_m; n = 6.072 dm3/22.4 dm3 = 0.27 mole;

if n (N₂) = 0.27 mole then n (NH₃) = 0.27 * 2 = 1.35 mole;

N (NH₃) = N_A * n = 6.02*10²³ * 1.35 mole = 8.127*10²³

Answer: N (NH₃) = 8.127*10²³