Question #169680

A 3.5g sample of pure metal requires 25.0 J of energy to change the temperature from 33 C to 42 C. What is the specific heat?




1
Expert's answer
2021-03-08T05:55:40-0500
Q=cmΔt,J/(kg∗K)Q=cm\Delta t, J/(kg*K)

c=Q/(mΔt)=25/(0.0035∗9)=793.65J/(kg∗K)c=Q/(m\Delta t)=25/(0.0035*9)=793.65 J/(kg*K)


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Place free inquiry
Calculate the price
Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!
Our fields of expertise
Submit Your Assignment. We Can Do It.
LATEST TUTORIALS
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult. You can find this expert in "Assignmentexpert.com" with confidence. Exceptional experts! I appreciate your help. God bless you!
Canada #340153 on Dec 2023