Chlorine gas occupies a volume of 25 mL at 300K. What volume will it occupy at 600K?
V1=25 mLT1=300 KT2=600 KP=constantV1T1=V2T2V2=V1×T2T1=25×600300=50 mLV_1 = 25 \;mL \\ T_1 = 300 \;K \\ T_2 = 600 \;K \\ P = constant \\ \frac{V_1}{T_1}= \frac{V_2}{T_2} \\ V_2 = \frac{V_1 \times T_2}{T_1} \\ = \frac{25 \times 600}{300} \\ = 50 \;mLV1=25mLT1=300KT2=600KP=constantT1V1=T2V2V2=T1V1×T2=30025×600=50mL
Answer: 50 mL
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment