Chlorine gas occupies a volume of 25 mL at 300K. What volume will it occupy at 600K?
"V_1 = 25 \\;mL \\\\\n\nT_1 = 300 \\;K \\\\\n\nT_2 = 600 \\;K \\\\\n\nP = constant \\\\\n\n\\frac{V_1}{T_1}= \\frac{V_2}{T_2} \\\\\n\nV_2 = \\frac{V_1 \\times T_2}{T_1} \\\\\n\n= \\frac{25 \\times 600}{300} \\\\\n\n= 50 \\;mL"
Answer: 50 mL
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