Question

Chlorine gas occupies a volume of 25 mL at 300K. What volume will it occupy at 600K? 

Answer 1

$V_1 = 25 \;mL \\ T_1 = 300 \;K \\ T_2 = 600 \;K \\ P = constant \\ \frac{V_1}{T_1}= \frac{V_2}{T_2} \\ V_2 = \frac{V_1 \times T_2}{T_1} \\ = \frac{25 \times 600}{300} \\ = 50 \;mL$

Answer: 50 mL