Answer to Question #169574 in General Chemistry for Tina

Question #169574

Laughing gas (nitrous oxide, N2O) is sometimes used as an anesthetic in dentistry. It is produced when ammonia nitrate is decomposed according to the following reaction.

NH4NO3(s) —> N2O(g) + 2H2O(l)

hkw many grams of NH4NO3 are required to produce 33.0 g N2O? Show your work.


1
Expert's answer
2021-03-08T05:54:16-0500

Molar mass of N2O = 44 g/m

So, 33.0 g N2O = 33g/(44 g/mol)

              = (3/4) mol

               

NH4NO3(s) —> N2O(g) + 2H2O(l)


From above balanced equation,

To produce 1 mole of N2O required 1 mole of NH4NO3 .

    So, (3/4) moles of N2O required (3/4) moles of NH4NO3


Molar mass of NH4NO3 = 80 g/mol

So, (3/4) moles of NH4NO3

    = (3/4)×80 grams

    = 60 grams

     

Hence, 60 grams of NH4NO3 are required to produce 33.0 g N2O.


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