Laughing gas (nitrous oxide, N2O) is sometimes used as an anesthetic in dentistry. It is produced when ammonia nitrate is decomposed according to the following reaction.
NH4NO3(s) —> N2O(g) + 2H2O(l)
hkw many grams of NH4NO3 are required to produce 33.0 g N2O? Show your work.
Molar mass of N2O = 44 g/m
So, 33.0 g N2O = 33g/(44 g/mol)
= (3/4) mol
NH4NO3(s) —> N2O(g) + 2H2O(l)
From above balanced equation,
To produce 1 mole of N2O required 1 mole of NH4NO3 .
So, (3/4) moles of N2O required (3/4) moles of NH4NO3
Molar mass of NH4NO3 = 80 g/mol
So, (3/4) moles of NH4NO3
= (3/4)×80 grams
= 60 grams
Hence, 60 grams of NH4NO3 are required to produce 33.0 g N2O.
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