Answer to Question #169374 in General Chemistry for Fabian Rodriguez

General Chemistry

Question #169374

For the reaction Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃, how many moles of lead iodide are produced from 350. g of potassium iodide?

Expert's answer

You

13:17

1) n(KI)= m(KI)/M(KI)= 350/166=2.108 mole

2) n(PI2)=n(KI)/2=2.108/2= 1.05 mole

Answer: 1.05 mole PbI2

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