Gaseous ethane CH3CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.601 g of ethane is mixed with 1.7 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 2 significant digits.
2CH3CH3 + 7O2 ----> 4CO2 + 6H2O
Moles of ethane = 0.601/30
= 0.020 mol
Moles of O2 = 1.7/32
= 0.053 mol
O2 is limiting reagent.
Mass of CO2 produced = 4×44×1.7/7×32
= 1.3 g
Mass of carbondioxide = [1.3] g
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