how many grams of O2 must you have to produce 14.6 grams of H2O answwr
The equation for the reaction
O2 + 2H2 →\to→ 2H2O
Moles of water used =massRMM=14.6g18.01528g/mol=0.81042mol=\dfrac{mass}{RMM} = \dfrac{14.6g}{18.01528g/mol}=0.81042mol=RMMmass=18.01528g/mol14.6g=0.81042mol
Mole ratio of O2 : H2O = 1:2
Moles of O2=12x0.81042=0.4052mol=\dfrac{1}{2}x0.81042 = 0.4052mol=21x0.81042=0.4052mol
Mass of O2 = moles x MM
= 0.4052mol x 31.998 =12.966g
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