A sample of Aluminium requires 4.0 J of energy to change its temp from 25 C to 32 C. What is the mass of the aluminum? Specific heat of Al = 0.89.
ΔE=mcΔTm=ΔEcΔTΔT=32−25=7 ºCm=4.00.89×7=0.64 gΔE = mcΔT \\ m = \frac{ΔE}{cΔT} \\ ΔT = 32 -25 = 7 \;ºC \\ m = \frac{4.0}{0.89 \times 7} = 0.64 \;gΔE=mcΔTm=cΔTΔEΔT=32−25=7ºCm=0.89×74.0=0.64g
Answer: 0.64 g
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