A sample of Aluminium requires 4.0 J of energy to change its temp from 25 C to 32 C. What is the mass of the aluminum? Specific heat of Al = 0.89.
"\u0394E = mc\u0394T \\\\\n\nm = \\frac{\u0394E}{c\u0394T} \\\\\n\n\u0394T = 32 -25 = 7 \\;\u00baC \\\\\n\nm = \\frac{4.0}{0.89 \\times 7} = 0.64 \\;g"
Answer: 0.64 g
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