Answer to Question #168778 in General Chemistry for Kayla

Question

Fe₂O₃+3CaS = Fe₂S₃+3CaO

How many grams of Fe₂O₃ are needed to produce 51.9 grams of CaO?

Answer 1

Solution:

Fe₂O₃ + 3CaS = Fe₂S₃ + 3CaO

x g 51,9 g

(Fe₂O₃) = 56*2+16*3= 160g/mol

(CaO)=40+16=56g/mol

Xmol(CaO)= 51,9/56= 0,96

Xmol(Fe₂O₃)=0,92/3=0,308

Xg(Fe₂O₃)=160*0,308/1=49,28

Answer:

m(Fe₂O₃)=49,28g