Question

Al₂O₃+3Na₂CO₃ ---> 3Na₂O+Al₂(CO₃)₃

If you have 9.56 moles of aluminum oxide. How many moles of sodium oxide could you produce?

Answer 1

Answer=28.68 moles

moles of Al₂O₃ =9.56 moles

Al₂O₃ is the limiting reactant since it has less moles as a reactant when we need equal moles of the reactants according to the reaction equation

We use the limiting reactant to calculate the moles of the products formed

Mole ratio of Al₂O₃ :Na₂O =1:3

Hence moles of Na₂O formed=9.56*3 = 28.68 moles