Question

If 10.4 mols of hydrogen, H2, and 9.1 mols of oxygen, O2, are placed together in a container and allowed to react according to the equation above, which one, if any, is in excess and by how much? also, how many moles of water, H2O, would be produced by the reaction?

Answer 1

Solution:

2H₂ + O₂ = 2H₂O

10,4mol   9,1mol

x_mol(O₂)=10,4/2=5,2

9,1-5,2=3,9
surplus(O2)= 3,9mol

Excess (O₂)=3,9mol

x_mol(H₂O)=10,4*2/2=10,4

Answer:

surplus(O2)= 3,9mol

H₂O=10,4 mol