Answer to Question #168625 in General Chemistry for inr

Question

The combustion of ammonia in the presence of excess oxygen yields NO₂ and H₂O:

4 NH₃ (g) + 7 O₂ (g) → 4 NO₂ (g) + 6 H₂O (g), The combustion of 28.8 g of ammonia consumes __________ g of oxygen.

Answer 1

moles of NH₃ = 28.8/17 = 1.694 moles

4 moles of NH₃ requires 7 moles of O₂

1 moles requires = 7/4 moles of O₂

1.694 moles requires = 1.694×7/4 = 2.964 moles of O₂

mass of O₂ = 2.964×32 = 94.848g