What is the molarity of a bleach solution containing 12.5g of NaOCl per liter of bleach?
the molecular weight of NaOC l is (22.9+16+34.45)=73.35
(22.9+16+34.45)=73.35this is from adding all the atomic weights from a periodic table. You then divide how many grams by the molecular mass (12.5/73.35)=.1 moles. therefore the molarity is .1/L. For the calcium hydroxide the molecular mass is 40+(2∗(16+1.008))=74.016
40+(2∗(16+1.008))=74.016This is how many grams one mole of calcium hydroxide weighs so .25∗1.5=0.375moles0.375∗74.016
=27.756grams
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