When 519 J up he is added to a sample of liquid water the temperature rises from 21.6 Celsius to 61.8 Celsius given the specific heat capacity of liquid water is 4.184J/G•K how many grams of water are in the sample
ΔT = 61.8 – 21.6 = 40.2 ºC
Q = mcΔT
Answer: 3.08 g
Comments
Leave a comment