The solubility of potassium trioxochlorate (V) at 20 degree Celsius is 8.0moldm3. calculate
a) at 20 degree Celsius 7.3 g will dissolve in100 g of water ml
250 g=250 ml
7.3=100
x=250
x=7.3×250100=18.25x=\frac{7.3\times250}{100}=18.25x=1007.3×250=18.25
b)с=8mol/l
M=122.548
Vs/s=0.02L
c=mM×Vc=\frac{m}{M\times V}c=M×Vm
m=c×M×V=8×122.548×0.02=19.61gm=c\times M\times V=8\times122.548\times0.02=19.61 gm=c×M×V=8×122.548×0.02=19.61g
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