Question

how many grams of NaoH are required to fully consume 3.10 grams of H2so4

Answer 1

$$n(H2SO4)=3.198=0.0315 mol$$

2NaOH+H2SO4=2H2O+Na2SO4

$$n(NaOH)/2=0.0315/1$$

$$n(NaOH)=0.0315*2=0.063$$

$$m(NaOH)=nM=0.063*40=2.52 g$$