Please with the steps:
2NaN3 (s) = 2Na(s) + 3N2 (g)
What volume of nitrogen gas measured at 1 atm and 9.00 °C is formed by the decomposition of 260 g of sodium azide?
Volume=............L
Volume of N2 at stp can be calculated using the reaction:
m(NaN3)/2*Mr(NaN3)=V(N2)/3*Vm;
V(N2)=m(NaN3)*3*Vm/2*Mr(NaN3)
m(NaN3)=260 g;
Mr(NaN3)= 23+3*14=65 g/mol;
Vm=22.4 L/mol;
V(N2)=260*3*22.4/(2*65)=134.4 L; - volume at stp
Volume of N2 at 90C(282 K) can be calculated using Charles's law:
V1/T1=V2/T2;
V2=V1T2/T1;
T1=0 oC=273 K;
V1=134.4 L
T2=282 K
V2=134.4*282/273=138.83 L
Answer: Volume=138.83 L
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