Calculations:
1.000 grams of Al = ________moles of Al
50 mL of 1.4 M KOH used = ________ moles of KOH
20 mL of 9.0 M H2SO4 = ___________moles of H2SO4
referring to the overall equation, the limiting reagent is? ____________
comments:
percent yield: 14.000/ theoretical yield x 100%
The theoretical yield is calculated using the overall equation:
2Al (s) + 2K+(aq) +2OH-(aq) + 8H+(aq) + 4SO42-(aq) + 22H2O(l) -> 2K[Al(SO4)2]. 12H2O + 3H2(g)
474.39 g/mol
1. 1/27= 0,037037037 moles of Al.
50 x 1.4/1000 = 0,07 moles of KOH.
20 x 9/1000 = 0.18 moles of H2SO4.
Limiting reagent is Al.
0.07/2 =0.035.
0.035 x 27 = 0.945 g of Al.
Percent yield is 94.5%.
Uses of Alum
Green chemistry is the design of chemical products and processes ... its design, manufacture, use, and ultimate disposal.
All hazards are assessed and categorized into three groups: biological, chemical and physical hazards. A general definition of a hazard as related to food safety is conditions or contaminants that can cause illness or injury.
Usually, percent yield is lower than 100% because the actual yield is often less than the theoretical value. Reasons for this can include incomplete or competing reactions and loss of sample during recovery.
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