Question

A 25 mL of 6M NaOH is diluted to 1.3L. What is the resulting concentration?

Answer 1

Here in both the cases the product of Molarity (concentration) and volume is equal.

$\Rightarrow$ $M_1V_1=M_2V_2$

where,

$M_1=6 M$

$V_1=25mL$

$M_2=M_2(let)$

$v_2=1.3 L=1.3\times1000=1300 mL$

Now,From the above formula

$\Rightarrow M_2=\dfrac{M_1V_1}{V_2}$

$\Rightarrow M_2=\dfrac{6\times25}{1300}=0.115 mL$

So the resulting concentration is $0.115mL.$