Answer to Question #167031 in General Chemistry for hnmk

Question

What mass, in grams, of argon gas occupy 125 cm3 at 32.0 oC and 103.5 kPa?

Answer 1

Given:-

$T=32^oC\Rightarrow32+273\Rightarrow305K$

$V=125cm^3\Rightarrow 0.125L$

$P=103.5kPa\Rightarrow1.0214 atm$

Since, from ideal gas equation

$\Rightarrow$ $PV=nRT$

$\Rightarrow$ $PV=\dfrac{given mass}{molarmass} \times{R}\times{T}$

$\Rightarrow$ $given mass=\dfrac{{P}\times{V}\times{molarmass}}{{R}\times{T}}$

$\Rightarrow$ $givenmass=\dfrac{{1.0124}\times{0.125}\times{39.948}}{{0.0821}\times{305}}$

$\Rightarrow givenmass=$ $0.2018$ $gm$

So, the mass of Argon gas is $0.2018 gm$