CH4 + 4Cl2–>CCl4 + 4HCl if 9.32 grams of CH4 react with 2.71 grams Cl2 how many grams of CCl4 will be produced?
In first, You must to definite the excess substance in this case. Let's look to given reaction:
CH4 + 4Cl2–>CCl4 + 4HCl
It follows from it, that for 16 g CH4 need to take 4*2*35.5 = 284 g Cl2. This means that there is an excess of CH4. Therefore, it is necessary to calculate by chlorine: 284 g Cl2 --> 35.5*4+12= 154 g CCl4. 2.71 g Cl2 --> 2.71* 154/284 = 1.47 g CCl4.
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