Calculate the molality of a sucrose solution made by dissolving 67.9 grams sucrose into 94.9 grams water. The molar mass of sucrose is 342.2 g/mol.
С (molality of sucrose) = n (sucrose)/m (water);
n (sucrose) = m/M = 67.9/342.2 = 0.2 mole;
С (molality of sucrose) = 0.2 mole/94.9 = 0.0021 mole/kg.
Answer: C = 0.0021 mole/kg.
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