Question

A sample of nitrogen gas occupies a volume of 1.3 L at 836 mm Hg and 2° C. The volume increases by 1.1 L and the temperature decreases to 27 K. What is the final pressure exerted on the gas in mm Hg? Round to two decimal places.

Answer 1

$V_1 = 1.3L\\ P_1 = 836mmHg \\ T_1 = 2°C = 275K$

$V_2 = 2.4L \\P_2 = ? \\ T_2 =248K$

from,

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$

$\dfrac{836×1.3}{275} = \dfrac{P_2×2.4}{248}$

$P_2 = \dfrac{836×1.3×248}{2.4×275} =$

408.37 mmHg.