Question

calculate the amount of electrical energy available from adry cell cooresponding to tje consumption of 6.55 g zinc metal(cell emf=1.5v, atm weight of zinc =65.5)

Answer 1

n(Zn) = $\frac{6.55}{65.5}$ = 0.1 (mol)

E = UQ = E(2nF) = 1.5(2$\times$0.1$\times$96485) = 28945.5 J.