What mass of carbon dioxide is present in 1.00 m3 of dry air at a temperature of 15 ∘C and a pressure of 689 torr?
Pressure, PPP = 689 torr = 91859.1 Pa
Volume, VVV = 1 m3 = 1000 L
Temperature, TTT = 15ο15^{\omicron}15ο C = 288 K
Molar mass of CO2, MMM = 44 g/mol
From Ideal gas equation,
PV=nRTPV=nRTPV=nRT
⇒n=PVRT\Rightarrow n=\dfrac{PV}{RT}⇒n=RTPV
⇒mM=PVRT\Rightarrow\dfrac{m}{M}=\dfrac{PV}{RT}⇒Mm=RTPV
⇒m=MPVRT\Rightarrow m=\dfrac{MPV}{RT}⇒m=RTMPV
⇒m=44×91859.1×10008.314×103×288\Rightarrow m=\dfrac{44\times91859.1\times1000}{8.314\times10^3\times288}⇒m=8.314×103×28844×91859.1×1000
⇒m=1687.99≈1688g\Rightarrow m=1687.99\approx1688g⇒m=1687.99≈1688g
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