Question

Calculate the mole fraction of each component of a solution containing 65g of ethanol (C2H6O) in 350g water.

Answer 1

Moler mass of Ethanol ($C_2H_6O$ )=46 g/mol

so moles of ethanol=$\dfrac{}{}$ $\dfrac{65}{46}$ =1.41 moles

Now moles of water = $\dfrac{350}{18}$ =19.45 moles

Total moles = 1.41+19.45=20.86 moles

Mole fraction of ethanol= moles of ethnol/total moles

$\Rightarrow$ $\dfrac{1.41}{20.86}$ =0.067

Mole fraction of water=moles of water/total moles

$\Rightarrow$ $\dfrac{19.45}{20.86}$ =0.932