At what temperature will 0.7 mole of chlorine exert a pressure of 1.18 atm at a volume of 0.75L?
find the formula:
"PV = nRT"
"R =\\frac{0.0821 atm.L}{mol.K}"
Volume = 0.75 L
Now we will put the values in formula.
"T = \\frac{PV}{nR}"
"T = \\frac{1.18 atm \u00d7 0.75 L}{ 0.07 mol \u00d70.0821 atm.L\/mol.K}"
T = 154 K
Comments
Leave a comment