Question

At what temperature will 0.7 mole of chlorine exert a pressure of 1.18 atm at a volume of 0.75L?

Answer 1

find the formula:

$PV = nRT$

$R =\frac{0.0821 atm.L}{mol.K}$

Volume = 0.75 L

Now we will put the values in formula.

$T = \frac{PV}{nR}$

$T = \frac{1.18 atm × 0.75 L}{ 0.07 mol ×0.0821 atm.L/mol.K}$

T = 154 K