A sample of sulfur dioxide occupies a volume of 549 mL at 47° C and 779 mm Hg. What volume will the sulfur dioxide occupy in ml at 2° C and 0.8 atm? Round to the nearest two decimal places.
"V_1 = 549 \\;mL \\\\\n\nT_1 = 47 + 273 = 320 \\;K \\\\\n\nP_1 = 779 \\;mmHg = 1.02 \\;atm\\\\\n\nT_2 = 2 + 273 = 275 \\;K \\\\\n\nP_2 = 0.8 \\;atm \\\\\n\n\\frac{P_1 \\times V_1}{T_1} = \\frac{P_2 \\times V_2}{T_2} \\\\\n\nV_2 = \\frac{P_1 \\times V_1 \\times T_2}{T_1 \\times P_2} \\\\\n\n= \\frac{1.02 \\times 549 \\times 275}{320 \\times 0.8} \\\\\n\n= 601.54 \\;mL"
Answer: 601.54 mL
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