Question

A sample of sulfur dioxide occupies a volume of 549 mL at 47° C and 779 mm Hg. What volume will the sulfur dioxide occupy in ml at 2° C and 0.8 atm? Round to the nearest two decimal places.

Answer 1

$V_1 = 549 \;mL \\ T_1 = 47 + 273 = 320 \;K \\ P_1 = 779 \;mmHg = 1.02 \;atm\\ T_2 = 2 + 273 = 275 \;K \\ P_2 = 0.8 \;atm \\ \frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2} \\ V_2 = \frac{P_1 \times V_1 \times T_2}{T_1 \times P_2} \\ = \frac{1.02 \times 549 \times 275}{320 \times 0.8} \\ = 601.54 \;mL$

Answer: 601.54 mL