Answer to Question #165308 in General Chemistry for orba

Question

How many grams of FeCl3 that will form if 1.0 g of each reactant mix?

Answer 1

2 Fe + 3 Cl₂ $\to$ 2 FeCl₃

Moles of Fe = 1g/56g•mol^-1 = 0.0178 moles

2 moles of Fe = 2 moles of FeCl₃

Grams of FeCl₃ = 0.0178× 162.2 = 2.88g