If 20.3 grams of an aqueous solution of barium sulfide, BaS, contains 2.59 grams of barium sulfide, what is the percentage by mass of barium sulfide in the solution?
______ % BaS
% by mass = "\\frac{mass of a component }{total mass }" ×100
% by mass = ( 2.59 / 20.3 ) × 100
% by mass = 12.75 %
12.75 % BaS
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