Answer to Question #164786 in General Chemistry for leya naumchuk

Question

What is the mass in grams of CuO that would be required to produce 41.50 moles of nitrogen gas in the following chemical reaction?

2 NH₃(g) + 3 CuO(s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)

Answer 1

$2 NH₃(g) + 3 CuO(s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)$

From the above balanced chemical equation....

To produce,

1 mole of N₂ gas 3 moles of CuO is needed

41.50 mole of N2 gas (41.50×3) moles of CuO is needed

= 124.5 mole of CuO needed

Molar mass of CuO = 79 g/mol

Mass of 124.5 mole of CuO = 9835.5 g CuO

Hence, to produce 41.50 moles of nitrogen gas according to the above reaction 9835.5 g CuO is needed.