Aqueous sulfuric acid H2SO4 will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate Na2SO4 and liquid water H2O
. Suppose 84. g of sulfuric acid is mixed with 19.3 g of sodium hydroxide. Calculate the maximum mass of sodium sulfate that could be produced by the chemical reaction. Round your answer to 3
significant digits.
NaOH + H2SO4→ Na2SO4 + H2O .
The mole ratio is 1:1
If 84g of sulfuric acid react = "84\/98.07=" 0.8565moles
Then 0.8565 moles of sodium sulfate are produced
Mass= 0.8565× 142= 121.627g
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