Answer to Question #163928 in General Chemistry for Jose Torres

Question

What would be the result if you combine 33 grams of methane with 289 grams of oxygen

Answer 1

CH₄+2O₂=CO₂+2H₂O

n(CH₄)=m/M=33/16=2.062mol

n(O₂)=m/M=289/32=9.03mol

n(CO₂)=2.062mol

m(CO₂)=n*M=2.062*44=90g

n(H₂O)=2*2.062=4.124mol

m(H₂O)=n*M=4.124*18=74g