What would be the result if you combine 33 grams of methane with 289 grams of oxygen
if you combine 33 grams of methane with 289 grams of oxygen you get water and carbon dioxide
The equation for the reaction is:
CH4 +2O2 → CO2 + 2H2O
IF 16 g CH4 +64 g O2 → 44 g CO2 + 36 g H2O
33g CH4 + 289g O2 will produce ??
16 g Methane produce 36 g water
Therefore, 33g CH4 will produce?
33 x 36/16= 74.25g H2O
CH4=16g
12g is carbon
therefore 33g of CH4 contains 33cx 12/16= 24.75 carbon
each mole of carbon (12g) burns to 44g of C02
Therefore, 24.75g carbon x 44/12 =90.75g of CO2
33g CH4 + 289g O2 → 90.75g CO2 + 74.25g H2O
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