Answer to Question #163745 in General Chemistry for heidi leffew

Question

a sample of 10.5 g of nitrogen reacts with 20.2 g of hydrogen to produce ammonia

Answer 1

N₂ +3H₂ $\to$ 2NH₃

no. Of moles of N₂ = 10.5g/28gmol^- = 0.375 mole

no. Of moles of H₂ = 20.2g/2gmol^- = 10.1 mole

Based on mole ratio, N₂ is limiting in this situation because there is more than enough H₂ but not enough N₂.

moles NH₃ can be produced = (0.375 moles N₂ × 2 moles NH₃ )/1 mole N₂ = 0.75 moles

grams of NH₃ = 0.75 × 17 = 12.75 g NH₃ produced