Balance the following half-equations
(i). MnO4–(aq) → MnO2(s)
(ii). SO42-(aq) → SO32-(aq)
(iii). AsH3(s) → H3AsO3(s)
1) MnO4- + 4H+ + 3e- →\to→ MnO2 + 2H2O
2) SO42−_4^{2-}42− (aq) + 2H+ + 2e- →\to→ SO32−_3^{2-}32− + H2O
3) AsH3 (s) + 3H2O →\to→ H3AsO3 + 6H+ + 6e-
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