How many grams of NO2 would be produced by the reaction of 14 g of N2?
Given: N2 + 2 O2 ----> 2 NO2
14g N2 ×"\\frac{1mol N_2}{28.0134g N_2}" × "\\frac{1mol NO_2}{1mol N_2}"
= 0.4997 mol NO2
0.4997 mol NO2 × "\\frac{46.0055 g NO_2}{1 mol NO_2}"
= 22.988 g NO2
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