Question

How many grams of NO₂ would be produced by the reaction of 14 g of N₂?

Given:   N₂   +   2 O₂  ---->   2 NO₂  

Answer 1

14g N₂ ×$\frac{1mol N_2}{28.0134g N_2}$ × $\frac{1mol NO_2}{1mol N_2}$

= 0.4997 mol NO₂

0.4997 mol NO₂ × $\frac{46.0055 g NO_2}{1 mol NO_2}$

= 22.988 g NO₂