Mass of C2H5OH = 1.25 g
Mass of H2O = 11.6 g
Mass percent of C2H5 OH
= 1.25 × 100 / 1.25 + 11.6
= 125 / 12.86
= 9.72 .
Mass percent of H2O = 100 - 9.72 = 90.28 %.
Molality
= moles of ethyl Alcohol/mass of solvent in kg
= 1.25 / 46 / 11.6 / 1000
= 1.25 × 1000 / 11.6 × 46
= 2.342578 mol / kg .
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