Question

given the reaction to CaH2 +2 H2O —> Ca(OH)2+2H2. if you have 95.4 g of CaH2, how many moles of CaH2 are there?

Answer 1

$CaH2(s) + 2H2O(l) → Ca(OH)2(aq) + 2 H2(g)$

1 Mol of CaH₂$= 42.09 g/mol$

$?=95.9 g$

$= 95.4/42.09$

$=2.3mol$ of CaH₂