given the reaction to CaH2 +2 H2O —> Ca(OH)2+2H2. if you have 95.4 g of CaH2, how many moles of CaH2 are there?
"CaH2(s) + 2H2O(l) \u2192 Ca(OH)2(aq) + 2 H2(g)"
1 Mol of CaH2"= 42.09 g\/mol"
"?=95.9 g"
"= 95.4\/42.09"
"=2.3mol" of CaH2
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